8x^2=-48x=-104

Solution for 8x^2=-48x=-104 equation:

8x^2=-48x=-104

We move all terms to the left:

8x^2-(-48x)=0

We get rid of parentheses

8x^2+48x=0

a = 8; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·8·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*8}=\frac{0}{16}
=0
$